1. The current gain of a BJT is

a. g

b. g

c. g

d. g

Solution: https://www.youtube.com/watch?v=NQcoEO5xLYk

2. The ideal OP-AMP has the following characteristics

a. R

b. R

c. R

d. R

Solution: https://www.youtube.com/watch?v=mtUl2BzGphU

3. Consider the following two statements :

a. Only statement 1 is correct.

b. Only statement 2 is correct.

c. Both the statements 1 and 2 are correct.

d. Both the statements 1 and 2 are incorrect.

Solution: https://www.youtube.com/watch?v=HQUPS3pY2A8

4. An NPN BJT has g

a. f

b. f

c. f

d. f

Solution: https://www.youtube.com/watch?v=VJJplixM0a8

5. The following circuit shown in the figure is

a. Hartley oscillator with f

b. Colpitts oscillator with f

c. Hartley oscillator with f

d. Colpitts oscillator with f

Solution: https://www.youtube.com/watch?v=U6V6gK9avGY

6. The inverting OP-AMP shown in the figure has an open loop gain of 100. The closed loop gain V

a. – 8

b. – 9

c. – 10

d. – 11

Solution: https://www.youtube.com/watch?v=JMZCkiOUJDI

7. In the figure, assume the OP-AMPs to be ideal. The output V

Solution: https://www.youtube.com/watch?v=E4dxhaGLiOA

8. An emitter follower amplifier is shown below, where Z

a. Draw the small signal equivalent circuit of the amplifier.

b. Obtain an expression for Z

c. Obtain an expression for Z

d. Determine Z

9. In the circuit shown, assume that the OP-AMP is ideal.

a. Obtain an expression for V

b. If R = 1 Ω, I

c. Suppose that the transistor in the feedback path is replaced by a PN junction diode with a reverse saturation current of I

a. g

_{m}r_{o}b. g

_{m }/ r_{o}c. g

_{m}r_{π}d. g

_{m }/ r_{π}2. The ideal OP-AMP has the following characteristics

a. R

_{i}= ∞, A_{V}= ∞, R_{o}= 0b. R

_{i}= 0, A_{V}= ∞, R_{o}= 0c. R

_{i}= ∞, A_{V}= ∞, R_{o}= ∞d. R

_{i}= 0, A_{V}= ∞, R_{o}= ∞3. Consider the following two statements :

**Statement 1:**Astable Multivibrator can be used for generating square wave.**Statement 2:**Bistable Multivibrator can be used for storing binary information.a. Only statement 1 is correct.

b. Only statement 2 is correct.

c. Both the statements 1 and 2 are correct.

d. Both the statements 1 and 2 are incorrect.

4. An NPN BJT has g

_{m}= 38 mA/volt, C_{µ}= 10^{-14}F, C_{π}= 4x10^{-13}F and DC current gain β = 90. For this transistor f_{τ}and f_{β}area. f

_{τ}= 1.64 x 10^{8}Hz and f_{β}= 1.47 x 10^{10}Hzb. f

_{τ}= 1.47 x 10^{10}Hz and f_{β}= 1.64 x 10^{8}Hzc. f

_{τ}= 1.33 x 10^{12}Hz and f_{β}= 1.47 x 10^{10}Hzd. f

_{τ}= 1.47 x 10^{10}Hz and f_{β}= 1.33 x 10^{12}Hz5. The following circuit shown in the figure is

a. Hartley oscillator with f

_{osc}= 79.6MHzb. Colpitts oscillator with f

_{osc}= 50.3MHzc. Hartley oscillator with f

_{osc}= 159.2MHzd. Colpitts oscillator with f

_{osc}= 159.2MHz6. The inverting OP-AMP shown in the figure has an open loop gain of 100. The closed loop gain V

_{o}/V_{s}isa. – 8

b. – 9

c. – 10

d. – 11

7. In the figure, assume the OP-AMPs to be ideal. The output V

_{o}of the circuit is8. An emitter follower amplifier is shown below, where Z

_{i}is the impedance looking into the base of the transistor and Z_{o}is the impedance looking into the emitter of the transistor.a. Draw the small signal equivalent circuit of the amplifier.

b. Obtain an expression for Z

_{i}.c. Obtain an expression for Z

_{o}.d. Determine Z

_{i}and Z_{o}, if a capacitor C is connected across R_{1}.**Solution:****https://www.youtube.com/watch?v=UH5_EioJdxU**9. In the circuit shown, assume that the OP-AMP is ideal.

a. Obtain an expression for V

_{o}in terms of V_{s}, R and the reverse saturation current I_{s}of the transistor.b. If R = 1 Ω, I

_{s}= 1 pA and the thermal voltage V_{T}= 25 mV, then what is the value of the output voltage V_{o}for an input voltage V_{s}of 1 volt?c. Suppose that the transistor in the feedback path is replaced by a PN junction diode with a reverse saturation current of I

_{s}. The P-side of the diode is connected to node A and the N-side to node B. then what is the expression for V_{o}in terms of V_{s}, R and I_{s}?**Solution:****https://www.youtube.com/watch?v=3YOkRQGOWbg**