Monday, May 12, 2014

GATE 2010 ECE Video Solution on Digital Circuits (Digital Electronics)

1. Match the logic gates in Column A with their equivalents in Column B.

a. P – 2, Q – 4, R – 1, S – 3
b. P – 4, Q – 2, R – 1, S – 3
c. P – 2, Q – 4, R – 3, S – 1
d. P – 4, Q – 2, R – 3, S – 1
Answer:D
Solution : https://www.youtube.com/watch?v=dkREztdPw8E


2. For the output F to be 1 in the logic circuit shown, the input combination should be

a. A = 1, B = 1, C = 0
b. A = 1, B = 0, C = 0
c. A = 0, B = 1, C = 0
d. A = 0, B = 0, C = 1
Answer:D
Solution : https://www.youtube.com/watch?v=pQAOPtOwtBk


3. In the circuit shown, the device connected to Y5 can have address in the range

a. 2000 – 20FF
b. 2D00 – 2DFF
c. 2E00 – 2EFF
d. FD00 – FDFF
Answer:B
Solution : https://www.youtube.com/watch?v=5P58M5A7t2U


4. Assuming that all flip-flops are in reset condition initially, the count sequence observed at QA in the circuit shown is



a. 0010111….
b. 0001011….
c. 0101111….
d. 0110100….
Answer:D
Solution : https://www.youtube.com/watch?v=UsicxIAMqx0


5. The Boolean function realized by the logic circuit shown is



a. F = ∑m(0,1,3,5,9,10,14)
b. F = ∑m(2,3,5,7,8,12,13)
c. F = ∑m(1,2,4,5,11,14,15)
d. F = ∑m(2,3,5,7,8,9,12)
Answer:D
Solution : https://www.youtube.com/watch?v=pOgzYeepujg


6. For the 8085 assembly language program given below, the content of the accumulator after the execution of the program is


3000   MVI A, 45H
3002   MOV B, A
3003   STC
3004   CMC
3005   RAR
3006   XRA B

a. 00H
b. 45H
c. 67H
d. E7H
Answer:C
Solution : https://www.youtube.com/watch?v=NSdbNs_Oiwk

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